深搜,从一点向各处搜找到所有能走的地方。
Red and Black
Time Limit: 1000MS | Memory Limit: 30000K | |
Total Submissions: 12004 | Accepted: 6097 |
Description
There is a rectangular room, covered with square tiles. Each tile is colored either red or black. A man is standing on a black tile. From a tile, he can move to one of four adjacent tiles. But he can't move on red tiles, he can move only on black tiles. Write a program to count the number of black tiles which he can reach by repeating the moves described above.
Input
The input consists of multiple data sets. A data set starts with a line containing two positive integers W and H; W and H are the numbers of tiles in the x- and y- directions, respectively. W and H are not more than 20. There are H more lines in the data set, each of which includes W characters. Each character represents the color of a tile as follows. '.' - a black tile '#' - a red tile '@' - a man on a black tile(appears exactly once in a data set) The end of the input is indicated by a line consisting of two zeros.
Output
For each data set, your program should output a line which contains the number of tiles he can reach from the initial tile (including itself).
Sample Input
6 9....#......#..............................#@...#.#..#.11 9.#..........#.#######..#.#.....#..#.#.###.#..#.#..@#.#..#.#####.#..#.......#..#########............11 6..#..#..#....#..#..#....#..#..###..#..#..#@...#..#..#....#..#..#..7 7..#.#....#.#..###.###...@...###.###..#.#....#.#..0 0
Sample Output
4559613
#includeusing namespace std; char map[22][22]; int sum,l,h; int dir[4][2]={ { 1,0},{ -1,0},{ 0,1},{ 0,-1}}; bool border(int x,int y) { if(x<0||x>=h||y<0||y>=l) return 0; return 1; } void search(int x,int y) { int i; int xx,yy; sum++; map[x][y]='#'; for(i=0;i<4;i++) { xx=x+dir[i][0]; yy=y+dir[i][1]; if(border(xx,yy)&&map[xx][yy]=='.') search(xx,yy); } } int main() { int i,j; int x0,y0; while(cin>>l>>h) { sum=0; if(l==0&&h==0)break; for(i=0;i >map[i][j]; if(map[i][j]=='@') { x0=i; y0=j; } } } search(x0,y0); cout< <